2x^2+16x+24/3x^2/x+6

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Solution for 2x^2+16x+24/3x^2/x+6 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x^2+16*x+((24/3)*x^2)/x+6 = 0

2*x^2+24*x+6 = 0

DELTA = 24^2-(2*4*6)

DELTA = 528

DELTA > 0

x = (528^(1/2)-24)/(2*2) or x = (-528^(1/2)-24)/(2*2)

x = (4*33^(1/2)-24)/4 or x = (-4*33^(1/2)-24)/4

x in { (-4*33^(1/2)-24)/4, (4*33^(1/2)-24)/4 }

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